On the disk shown above, a player spins the arrow twice. The fraction a/b is formed, where a is the number of the sector where the arrow stops after the first spin and b is the number of the sector where the arrow stops after the second spin. on every spin, each of the numbered sectors has an equal probability of being the sector on which the arrow stops. What is the probability that the fraction a/b is greater than 1?
(the sections are supposed to all be equal by the way...)
and the book says that the answer is A. If anyone knows how to do this and wishes to enlighten me, I would greatly appreciate it!